How do you find the quotient of #(14x^2+7x)div7x#?

Answer 1

#2x +1#

You can compare this to

#3x(5x+4) = 15x^2 +12x#
where the #" "3x" "# is multiplied by both terms inside the bracket using the distributive law,
#(14x^2 +7x)div 7x" "# can be written as #" "1/(7x)(14x^2 +7x)#
Or as #" "(14x^2 +7x)/(7x)#
Or as separate terms: #" "(14x^2)/(7x) +(7x)/(7x)#
Whichever you choose, each of the terms has to be divided by #7x#
#=2x +1#
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Answer 2

See a solution process below:

First, rewrite the expression as:

#(14x^2 + 7x)/(7x) => (14x^2)/(7x) + (7x)/(7x) => (14x^2)/(7x) + 1#
Next, factor #7x# out of the numerator and denominator in the fraction on the left giving:
#(7x xx 2x)/(7x xx 1) + 1 => (color(red)(cancel(color(black)(7x))) xx 2x)/(color(red)(cancel(color(black)(7x))) xx 1) + 1 => (2x)/1 + 1 =>#
#2x + 1#
However, from the original expression we cannot divide by #0# therefore we need the exclusion:
Where: #7x != 0# or #x != 0#
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Answer 3

To find the quotient of (14x^2+7x) divided by 7x, you divide each term in the numerator by the denominator. The quotient is 2x + 1.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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