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How do you find the quotient #(6x^2+10x)div2x#?

Answer 1

Ethan Adkins

See the entire solution process below:

First, rewrite this expression as:

#(6x^2 + 10x)/(2x)#

Next, factor #color(red)(2x)# from the term in the numerator:

#((color(red)(2x) xx 3x) + (color(red)(2x) xx 5))/(2x)#

#(color(red)(2x)(3x + 5))/(2x)#

Then, cancel the common terms in the numerator and denominator:

#(cancel(color(red)(2x))(3x + 5))/color(red)(cancel(color(black)(2x)))#

#3x + 5#, when #2x != 0# or #x != 0#

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Answer 2

Abigail Allen

To find the quotient of (6x^2 + 10x) divided by 2x, you divide each term of the numerator by the denominator.

First, divide 6x^2 by 2x, which gives you 3x. Next, divide 10x by 2x, which gives you 5.

Therefore, the quotient is 3x + 5.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.