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How do you find the product of #((r-8)(r+3))/r*(2r)/((r+8)(r+3))#?

Answer 1

Julia Adams

#color(green)((2(r-8))/((r+8))#

#((r-8)(cancel(r+3)^color(red)1))/cancelr^color(red)1*(2cancelr^color(red)1)/((r+8)(cancel(r+3)^color(red)1)#

#:.=color(green)((2(r-8))/((r+8))#

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Answer 2

Eva Abramson

To find the product of ((r-8)(r+3))/r*(2r)/((r+8)(r+3)), we can simplify the expression by canceling out common factors in the numerator and denominator.

First, we can cancel out the common factor of (r+3) in the numerator and denominator.

This leaves us with (r-8)/r * 2r/(r+8).

Next, we can simplify further by canceling out the common factor of r in the numerator and denominator.

This gives us (r-8) * 2/(r+8).

Therefore, the product of ((r-8)(r+3))/r*(2r)/((r+8)(r+3)) simplifies to (r-8) * 2/(r+8).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.