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How do you find the product of #(m+5)(m^2+4m-8)#?

Answer 1

Eva Abramson

#=m^3+9m^2+12m-40#

By multiplying each term of the first polynomial by each term of the second one:

#m(m^2+4m-8)+5(m^2+4m-8)#

#=m^3+4m^2-8m+5m^2+20m-40#

#=m^3+9m^2+12m-40#

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Answer 2

Genesis Allen

To find the product of (m+5)(m^2+4m-8), you use the distributive property:

(m+5)(m^2+4m-8) = m(m^2+4m-8) + 5(m^2+4m-8)

= m^3 + 4m^2 - 8m + 5m^2 + 20m - 40

Combine like terms:

= m^3 + (4m^2 + 5m^2) + (-8m + 20m) - 40

= m^3 + 9m^2 + 12m - 40

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.