Home > Algebra > Multiplication of Polynomials by Binomials

How do you find the product of #(m+3)(m^2+3m+5)#?

Answer 1

#m^3+6m^2+14m+15#

#(m+3)(m^2+3m+5)#

To expand the polynomial multiply each element of the first term by each element of the second term and then combine the coefficients of each power.

#(m+3)(m^2+3m+5) = m(m^2+3m+5) +3(m^2+3m+5)#

#=m^3+3m^2+5m + 3m^2 +9m+15#

#=m^3 +(3+3)m^2 + (5+9)m +15#

#= m^3+6m^2+14m+15#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Savannah Anderson

To find the product of (m+3)(m^2+3m+5), you can use the distributive property or the FOIL method, which stands for First, Outer, Inner, Last.

First, multiply m by each term inside the second parenthesis: m * m^2 = m^3 m * 3m = 3m^2 m * 5 = 5m

Then, multiply 3 by each term inside the second parenthesis: 3 * m^2 = 3m^2 3 * 3m = 9m 3 * 5 = 15

Combine like terms: m^3 + 3m^2 + 5m + 9m + 15

So, the product of (m+3)(m^2+3m+5) is: m^3 + 3m^2 + 5m + 9m + 15

Simplify the expression: m^3 + 3m^2 + 14m + 15

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.