# How do you find the product of #(3x^3)/(8x)*16/x#?

If you cancel factors in the numerator and denominator first, it makes the numbers smaller.

Cancel the numbers and simplify the variables in the denominators by adding the indices:

To divide with indices, subtract them:

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You will need to multiply the numbers *top X top*, and *bottom X bottom* and add the exponents in the same way. After that you will need to simplify by dividing and exponent subtraction if necessary.

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To find the product of (3x^3)/(8x) and 16/x, we can simplify the expression by canceling out common factors.

First, we can simplify (3x^3)/(8x) by canceling out the common factor of x in the numerator and denominator. This leaves us with (3x^2)/8.

Next, we can simplify 16/x by canceling out the common factor of x in the numerator and denominator. This leaves us with 16.

Therefore, the product of (3x^3)/(8x) and 16/x is (3x^2)/8 * 16, which simplifies to 6x^2.

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To find the product of (\frac{3x^3}{8x} \times \frac{16}{x}), follow these steps:

- Multiply the numerators together: (3x^3 \times 16 = 48x^3).
- Multiply the denominators together: (8x \times x = 8x^2).
- Simplify the fraction by dividing the numerator by the denominator: (\frac{48x^3}{8x^2}).
- Reduce the fraction: (48 \div 8 = 6) and (x^3 \div x^2 = x).
- The final result is (6x).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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