How do you find the product of #(3ab)/(4c^4)*(16c^2)/(9b)#?

Question

Kennedy Adams · Accepted Answer

#(4a)/(3c^2)#

Step 1) Multiple both terms in the numerators of the fractions and multiple both terms in the denominators of the fractions:

#(3ab*16c^2)/(4c^4 9b)#

#(48abc^2)/(36bc^4)#

Step 2) Separate like terms to simplify:

#(48/36)a(b/b)(c^2/c^4)#

#(12/12)(4/3)a(1)(1/c^(4-2))#

#(4/3)a(1/c^2)#

Step 3) Combine all of the terms back again for the final simplification:

#(4a)/(3c^2)#

Abigail Allen · Answer

undefined To find the product of (3ab)/(4c^4)*(16c^2)/(9b), you can simplify the expression by canceling out common factors in the numerator and denominator.

First, cancel out the common factors of b in the numerator and denominator: (3ab)/(4c^4)*(16c^2)/(9b) = (3a)/(4c^4)*(16c^2)/(9)

Next, cancel out the common factors of c^2 in the numerator and denominator: (3a)/(4c^4)*(16c^2)/(9) = (3a)/(4c^2)*(16)/(9)

Now, multiply the numerators together and the denominators together: (3a * 16)/(4c^2 * 9)

Simplify the numerator: 48a

Simplify the denominator: 36c^2

Therefore, the product of (3ab)/(4c^4)*(16c^2)/(9b) is 48a/36c^2, which can be further simplified to 4a/3c^2.