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How do you find the product of #(2m-3)(m+4)#?

Answer 1

See full process explanation below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(2m) - color(red)(3))(color(blue)(m) + color(blue)(4))# becomes:

#(color(red)(2m) xx color(blue)(m)) + (color(red)(2m) xx color(blue)(4)) - (color(red)(3) xx color(blue)(m)) - (color(red)(3) xx color(blue)(4))#

#2m^2 + 8m - 3m - 12#

We can now combine like terms:

#2m^2 + (8 - 3)m - 12#

#2m^2 + 5m - 12#

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Answer 2

Eva Adamson

To find the product of (2m-3)(m+4), you can use the distributive property or the FOIL method. First, multiply each term in the first parentheses by each term in the second parentheses:

(2m)(m) + (2m)(4) + (-3)(m) + (-3)(4)

Next, simplify each term:

2m^2 + 8m - 3m - 12

Combine like terms:

2m^2 + 5m - 12

So, the product of (2m-3)(m+4) is 2m^2 + 5m - 12.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.