How do you find the product #(8d+3)(5d+2)#?

Answer 1

See the entire solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(8d) + color(red)(3))(color(blue)(5d) + color(blue)(2))# becomes:

#(color(red)(8d) xx color(blue)(5d)) + (color(red)(8d) xx color(blue)(2)) + (color(red)(3) xx color(blue)(5d)) + (color(red)(3) xx color(blue)(2))#

#40d^2 + 16d + 15d + 6#

We can now combine like terms:

#40d^2 + (16 + 15)d + 6#

#40d^2 + 31d + 6#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Julia Adams

To find the product (8d+3)(5d+2), you use the distributive property and multiply each term in the first expression by each term in the second expression, then combine like terms. The result is: 40d^2 + 16d + 15d + 6. Simplify this to get the final answer: 40d^2 + 31d + 6.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.