How do you find the prime factorization of the number 3,240?

Answer 1

#3240=2xx2xx2xx3xx3xx3xx3xx5#

It is apparent that #3240# is divisible by #40# and dividing #3240# by #40#, we get #81#. Let us now use tree method to find the prime factors of the number #3,240#.

Doing so leads to following:

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Answer 2

To find the prime factorization of the number 3,240:

  1. Begin by dividing the number by the smallest prime number, which is 2.
  2. Continue dividing by prime numbers until the quotient becomes 1.
  3. Write down all the prime factors you used in the divisions.
  4. The prime factorization of 3,240 will be the product of these prime factors.

Here's how the process works:

3,240 ÷ 2 = 1,620 1,620 ÷ 2 = 810 810 ÷ 2 = 405 405 ÷ 3 = 135 135 ÷ 3 = 45 45 ÷ 3 = 15 15 ÷ 3 = 5 5 is already a prime number.

Now, let's list all the prime factors used in the divisions:

2, 2, 2, 3, 3, 3, 3, 5

Therefore, the prime factorization of 3,240 is:

2^3 × 3^4 × 5

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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