# How do you find the points of intersection of #r=3+sintheta, r=2csctheta#?

Polar coordinates of points of intersection are

These are depicted in rectangular coordinates as shown below. graph{(y-2)(x^2+y^2-y-3sqrt(x^2+y^2))=0 [-10, 10, -5, 5]}

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To find the points of intersection of the polar curves ( r = 3 + \sin(\theta) ) and ( r = 2\csc(\theta) ), set them equal to each other: ( 3 + \sin(\theta) = 2\csc(\theta) ). Solve this equation for ( \theta ) to find the values of ( \theta ) where the curves intersect. Then, substitute these values of ( \theta ) back into either of the original equations to find the corresponding values of ( r ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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