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How do you find the point-slope form of the equation of the line passing through the point (-1, -3) and has slope 5?

Answer 1

The main formula of a line is; #y=ax+b#

We should use one point to find the real equation. If we use (-1,-3) point; #y= ax+b => -3=-a+b#; a is the slope of the equation, we found that as #5#; #-3=(5*-1) + b => -3=-5 +b => b=2#; So the equation of the line will be; #y=ax+b => ul (y= 5x+2)#

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Answer 2

Nathan Axel

To find the point-slope form of the equation of the line passing through the point (-1, -3) with slope 5, use the formula: ( y - y_1 = m(x - x_1) ), where ( (x_1, y_1) ) is the given point and ( m ) is the slope. Substituting the values: ( y - (-3) = 5(x - (-1)) ). Simplify to get the point-slope form: ( y + 3 = 5(x + 1) ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.