How do you find the perimeter and area of an isosceles triangle whose base is 6cm, leg is 5cm and height is 4cm?
Have a look:
Consider the diagram:
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To find the perimeter and area of an isosceles triangle with a base of 6 cm, a leg of 5 cm, and a height of 4 cm, follow these steps:

Perimeter: [ \text{Perimeter} = \text{Sum of all sides} ]

Area: [ \text{Area} = \frac{1}{2} \times \text{Base} \times \text{Height} ]
Let's calculate:

Perimeter: [ \text{Perimeter} = 6 + 5 + 5 = 16 , \text{cm} ]

Area: [ \text{Area} = \frac{1}{2} \times 6 \times 4 = 12 , \text{cm}^2 ]
Therefore, the perimeter of the isosceles triangle is ( 16 , \text{cm} ) and the area is ( 12 , \text{cm}^2 ).
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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