How do you find the perimeter and area of an isosceles triangle whose base is 6cm, leg is 5cm and height is 4cm?

Answer 1

Have a look:

Consider the diagram:

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Answer 2

To find the perimeter and area of an isosceles triangle with a base of 6 cm, a leg of 5 cm, and a height of 4 cm, follow these steps:

  1. Perimeter: [ \text{Perimeter} = \text{Sum of all sides} ]

  2. Area: [ \text{Area} = \frac{1}{2} \times \text{Base} \times \text{Height} ]

Let's calculate:

  1. Perimeter: [ \text{Perimeter} = 6 + 5 + 5 = 16 , \text{cm} ]

  2. Area: [ \text{Area} = \frac{1}{2} \times 6 \times 4 = 12 , \text{cm}^2 ]

Therefore, the perimeter of the isosceles triangle is ( 16 , \text{cm} ) and the area is ( 12 , \text{cm}^2 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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