# How do you find the partial sum of #Sigma (2n+5)# from n=1 to 20?

Before we proceed a few identities

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To find the partial sum of the series Σ(2n + 5) from n = 1 to 20, you can use the formula for the sum of an arithmetic series:

S = n/2 * (first term + last term)

First, find the first term of the series when n = 1:

2(1) + 5 = 7

Next, find the last term of the series when n = 20:

2(20) + 5 = 45

Now, substitute these values into the formula:

S = 20/2 * (7 + 45) S = 10 * 52 S = 520

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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