How do you find the partial derivative of the function #f(x,y)=intcos(-7t^2-6t-1)dt#?

Answer 1
You need to be more specific about how #f# depends on #x# and #y#. Are they in the limits of the integral? Are they part of the integrand function? As you wrote it, there's no #x# or #y# dependence on the right-hand side and the derivatives with respect to #x# and #y# would be zero.
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Answer 2

To find the partial derivative of the function ( f(x, y) = \int \cos(-7t^2 - 6t - 1) dt ) with respect to ( x ), we first need to evaluate the integral with respect to ( t ) to eliminate the integral sign. After that, we differentiate the resulting expression with respect to ( x ). Since there is no explicit dependence of ( x ) in the integrand, the partial derivative of ( f(x, y) ) with respect to ( x ) would be zero.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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