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How do you find the parametric equations of line that passes through the points (1, 3, 2) and ( -4, 3, 0)?

Answer 1

Charles Arocha

The equation is #((x),(y),(z))=((1),(3),(2))+t((-5),(0),(-2))#

Let the points be

#A=(1,3,2)#

#B=(-4,3,0)#

The vector

#vec(AB)=((-4),(3),(0))-((1),(3),(2))=((-5),(0),(-2))#

The parametric equation of the line is

#((x),(y),(z))=((1),(3),(2))+t((-5),(0),(-2))#, #AA t in RR#

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Answer 2

Christopher Agresta

To find the parametric equations of the line passing through the points ((1, 3, 2)) and ((-4, 3, 0)), you first need to determine the direction vector of the line by subtracting the coordinates of one point from the other. Then, choose one of the points as the initial point on the line. Finally, express the parametric equations using the initial point and the direction vector.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.