How do you find the parallel and perpendicular slope of 3x-5y=-8?
Parallel slope =
The slopes of perpendicular lines are negative reciprocals of one another, as we can demonstrate:
Slop should be turned upside down and the sign changed to find the negative reciprocal.
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To find the slope of a line in the form ( ax + by = c ), rewrite the equation in slope-intercept form ( y = mx + b ), where ( m ) is the slope.
For the given equation ( 3x - 5y = -8 ), rearrange it to solve for ( y ):
[ 3x - 5y = -8 ] [ -5y = -3x - 8 ] [ y = \frac{3}{5}x + \frac{8}{5} ]
The slope of the line is ( \frac{3}{5} ).
For parallel lines, the slopes are equal. Therefore, the parallel slope is also ( \frac{3}{5} ).
For perpendicular lines, the slopes are negative reciprocals of each other. The negative reciprocal of ( \frac{3}{5} ) is ( -\frac{5}{3} ). Therefore, the perpendicular slope is ( -\frac{5}{3} ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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- What is the equation of the parabola that has a vertex at # (-2, -4) # and passes through point # (-3,-15) #?
- How do you find the slope perpendicular to #x = –2y + 10.#?
- What is the equation of the line with slope # m= 1/7 # that passes through # (-3/11,2/3) #?

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