How do you find the numerical value of one trigonometric function of x if tan x/cot x - sec x/cos x = 2/csc x ???

Answer 1

210 degree

Given, #(tanx)/(cotx)-(secx)/(cosx)=2/cscx# #rArr tanx/(1/tanx)-sec/(1/secx)=2sinx# #rArr tan^2x-sec^2x=2sinx#[As #sec^2x-tan^2x = 1]# #rArr -1=2sinx# #rArr sinx = -1/2# #rArr sinx = sin(180+30)# #rArr x=210#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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