How do you find the number of distinguishable permutations of the letters HONEST?

Answer 1

#6xx5xx4xx3xx2xx1=720#

Since all #6# letters in HONEST are distinct there are #6# choices for the first letter;
Once a first letter has been chosen there are #5# choices for the second letter; so there are #6xx5 =30# choices for the permutations of the first and second letters.
Once the first and second letters have been chosen there are #4# choices for the third letter; so there are #6xx5xx4# choices for the permutations of the first three letters.

...and so on.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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