How do you find the molar mass of #"Fe"_2"O"_3#?

Question

Cameron Andrews · Accepted Answer

Here's how you can do that.

As you know, the molar mass of a compound tells you the mass of exactly one mole of said element. You can calculate the molar mass of a compound by using In this case, a formula unit of iron(III) oxide, #"Fe"_2"O"_3#, consists of This means that one mole of iron(III) oxide will contain Now, the molar masses of iron and of oxygen are listed as #M_("M Fe") = "55.845 g mol"^(-1)# #M_("M O") = "15.9994 g mol"^(-1)# This tells you that one mole of iron has a mass of #"55.845 g"# and one mole of oxygen has a mass of #"15.9994 g"#. Use these values to find the mass of one mole of iron(III) oxide #overbrace(2 xx "55.845 g")^(color(blue)("the contribution of 2 moles of Fe")) + overbrace(3 xx "15.9994 g")^(color(purple)("the contribution of 3 moles of O")) = "159.6882 g"# So, if one mole of iron(III) oxide has a mass of #"159.6882 g"#, it follows that its molar mass will be #M_("M Fe"_2"O"_3) = color(green)(|bar(ul(color(white)(a/a)color(black)("159.6882 g mol"^(-1))color(white)(a/a)|)))#

Mateo Aguilar · Answer

undefined To find the molar mass of Fe2O3, you first need to determine the atomic masses of the elements involved. The atomic mass of Fe (iron) is approximately 55.845 grams per mole, and the atomic mass of O (oxygen) is approximately 15.999 grams per mole. Fe2O3 consists of 2 Fe atoms and 3 O atoms. Multiply the atomic mass of Fe by 2, and the atomic mass of O by 3. Then, add the results together to find the molar mass of Fe2O3.