How do you find the maximum value of # Y= 2(x+5)²8#?
The maximum value of the function is
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To find the maximum value of the function ( Y = 2(x + 5)^2  8 ), you can follow these steps:

Recognize that the given function is a quadratic function in the form ( Y = a(x  h)^2 + k ), where ( a ) is the coefficient of the squared term, and ( (h, k) ) represents the coordinates of the vertex of the parabola.

In the given function, ( a = 2 ), ( h = 5 ), and ( k = 8 ).

The vertex of the parabola is at the point ( (h, k) = (5, 8) ).

Since the coefficient of the squared term ( a = 2 ) is negative, the parabola opens downwards. Therefore, the vertex represents the maximum point of the function.

Therefore, the maximum value of the function ( Y ) occurs at the vertex ( (5, 8) ), and the maximum value of ( Y ) is ( 8 ).
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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