# How do you find the maximum or minimum of #f(x)=x^2+6x-2#?

differentiate f(x) and equate to zero.

• If f'' (a) > 0 then minimum

• If f'' (a) > 0 then maximum

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To find the maximum or minimum of ( f(x) = x^2 + 6x - 2 ), follow these steps:

- Find the derivative ( f'(x) ) of the function.
- Set ( f'(x) = 0 ) and solve for ( x ) to find critical points.
- Use the second derivative test or analyze the behavior of the function around critical points to determine whether each critical point corresponds to a maximum or minimum.
- If the second derivative test is inconclusive, you may need to consider additional methods, such as evaluating the function at endpoints of a given interval or using other techniques.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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- For what values of x is #f(x)=(x-1)(x-3)(x+12)# concave or convex?
- How do you find local maximum value of f using the first and second derivative tests: #2x^3-3x^2-36x-3#?
- How do you graph the derivative of #f(x) = cos(x)#?

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