How do you find the mass of sodium required to produce 5.68 L of hydrogen gas STP from the reaction described by the following equation: #2Na + 2H_2O -> 2NaOH + H_2#?

Answer 1

Use the balanced equation to relate the number of moles of sodium to hydrogen.

Calculate the number of moles required from the volume of hydrogen and then calculate the mass of sodium in the correct molar ratio.

The balanced equation shows that two moles of sodium will produce one mole of hydrogen gas. Using the ideal gas laws we could find that 1 mole of a gas is 22.4L volume.

Therefore, 5.68L #H_2# is #(5.68/22.4)*((L)/("L/mol")) = 0.254 "Mole" H_2#
With a ratio of # (2/1) ((Na)/(H_2))# we will need twice as many moles of sodium, or 0.507 moles of sodium.
Multiplying this value by the molecular weight of sodium gives us the mass required: #0.507mol * 23 (g/(mol)) = 11.67 grams Na#
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Answer 2

To find the mass of sodium required to produce 5.68 L of hydrogen gas at STP, you can use stoichiometry. First, balance the equation to determine the mole ratio between sodium and hydrogen gas. Then, use the molar volume of a gas at STP (22.4 L/mol) to convert the volume of hydrogen gas to moles. Finally, use the mole ratio from the balanced equation to find the moles of sodium required and then convert moles to grams using the molar mass of sodium (22.99 g/mol).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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