# How do you find the magnitude of YZ given Y(5,0) and Z(7,6)?

# bb(vec(YZ)) = ( (2), (6) ) \ \ # and# \ \ abs(bb(vec(YZ))) = 2sqrt(10) #

So in vector notation we can write:

Method 1:

Using the coordinates along, we can apply pythagoras theorem:

Method 2:

We have:

And so:

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You can find the magnitude of YZ using the distance formula, which states that the distance between two points (x1, y1) and (x2, y2) in a coordinate plane is given by the formula:

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Given Y(5,0) and Z(7,6), plug the coordinates into the formula:

[ d = \sqrt{(7 - 5)^2 + (6 - 0)^2} ]

[ d = \sqrt{(2)^2 + (6)^2} ]

[ d = \sqrt{4 + 36} ]

[ d = \sqrt{40} ]

[ d = 2\sqrt{10} ]

So, the magnitude of YZ is ( 2\sqrt{10} ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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