How do you find the Maclaurin Series for #f(x) = ln(cosx)#?
It's helpful to know Maclaurin Series for certain functions:
To get the Maclaurin Series for So the Maclaurin Series for
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To find the Maclaurin series for ( f(x) = \ln(\cos x) ), you can use the Taylor series expansion formula centered at ( x = 0 ), known as the Maclaurin series.
- First, find the derivatives of ( f(x) ) with respect to ( x ) up to the desired order.
- Evaluate these derivatives at ( x = 0 ).
- Use the formula for the Maclaurin series expansion, which involves the nth derivative of ( f(x) ) evaluated at ( x = 0 ) divided by ( n! ), multiplied by ( x^n ).
- Sum up these terms to get the series representation.
The Maclaurin series expansion for ( f(x) = \ln(\cos x) ) would look like this:
[ f(x) = \ln(\cos x) = \sum_{n=0}^{\infty} \frac{f^{(n)}(0)}{n!} \cdot x^n ]
To get the series, you'll need to compute the derivatives of ( f(x) ) with respect to ( x ) and then evaluate them at ( x = 0 ). Afterward, you can plug these values into the series representation formula.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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