How do you find the line with a slope of 3/4 that passes through (0,4)?

Question

Genesis Allen · Accepted Answer

#y=3/4x+4# #"the equation of a line in "color(blue)"slope-intercept form"# is. #•color(white)(x)y=mx+b# #"where m is the slope and b the y-intercept"# #"here "m=3/4" and y-intercept "=4larr(0,color(red)(4))# #rArry=3/4x+4larrcolor(red)"is the equation"#

Genesis Allen · Answer

#y=3/4x+4# The gradient is #3/4# and the coordinate you are given is the #y# intercept.

Isaiah Anthony · Answer

undefined To find the equation of the line with a slope of $ \frac{3}{4} $ that passes through the point $ (0,4) $, you can use the point-slope form of a linear equation, which is $ y - y_1 = m(x - x_1) $. Substituting the given values $ x_1 = 0 $, $ y_1 = 4 $, and $ m = \frac{3}{4} $, we get:

$$ y - 4 = \frac{3}{4}(x - 0) $$

Simplifying further:

$$ y - 4 = \frac{3}{4}x $$

$$ y = \frac{3}{4}x + 4 $$

So, the equation of the line is $ y = \frac{3}{4}x + 4 $.

Hazel Anglin · Answer

undefined To find the line with a slope of $ \frac{3}{4} $ that passes through the point $ (0,4) $, you can use the point-slope form of a linear equation. The point-slope form is given by $ y - y_1 = m(x - x_1) $, where $ (x_1, y_1) $ is the given point and $ m $ is the slope.

Substituting $ m = \frac{3}{4} $ and $ (x_1, y_1) = (0,4) $ into the point-slope form, we get:

$$ y - 4 = \frac{3}{4}(x - 0) $$

Simplify this equation:

$$ y - 4 = \frac{3}{4}x $$

$$ y = \frac{3}{4}x + 4 $$

So, the equation of the line with a slope of $ \frac{3}{4} $ that passes through the point $ (0,4) $ is $ y = \frac{3}{4}x + 4 $.