# How do you find the limit of #(x-sinx)/ (x^3)# as x approaches 0?

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To find the limit of (x - sinx) / (x^3) as x approaches 0, we can use L'Hôpital's Rule. Taking the derivative of the numerator and denominator separately, we get (1 - cosx) / (3x^2). Substituting x = 0 into this expression, we get (1 - cos0) / (3(0)^2) = 1/0 = undefined. Therefore, the limit does not exist.

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