How do you find the limit of # (x-pi)/(sinx)# as x approaches pi?
The answer
show the steps
we must use L'Hopital's Rule
By signing up, you agree to our Terms of Service and Privacy Policy
To find the limit of (x - pi)/(sinx) as x approaches pi, we can use L'Hôpital's rule. By differentiating the numerator and denominator, we get 1/(cosx). Substituting x = pi into this expression, we find that the limit is 1.
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- For what values of x, if any, does #f(x) = 1/((x+1)(x-6)) # have vertical asymptotes?
- How do you find the limit of # [1/(3+X)]- (1/3) ÷ X# as x->0?
- How do you find the limit of #(1/x)^x# as x approaches infinity?
- How do you find the limit of #(3x+1/x) - (1/sinx)# as x approaches 0 using l'hospital's rule?
- How do you find the limit of #ln ( (x+1) / x )# as x approaches infinity?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7