How do you find the limit of #(x^2 - 8) / (8x-16)# as x approaches #0^+#?
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Christopher AllersTo find the limit of (x^2 - 8) / (8x-16) as x approaches 0^+, we can substitute 0 into the expression and simplify. By substituting 0 for x, we get (-8) / (-16), which simplifies to 1/2. Therefore, the limit of (x^2 - 8) / (8x-16) as x approaches 0^+ is 1/2.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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