# How do you find the limit of # (x^2 - 4x + 5) # as x approaches #2#?

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To find the limit of a function as x approaches a specific value, we can directly substitute that value into the function.

In this case, we substitute x = 2 into the function (x^2 - 4x + 5):

(2^2 - 4(2) + 5) = 4 - 8 + 5 = 1

Therefore, the limit of (x^2 - 4x + 5) as x approaches 2 is 1.

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To find the limit of ( (x^2 - 4x + 5) ) as ( x ) approaches 2, you can directly substitute ( x = 2 ) into the expression:

[ (2^2 - 4 \cdot 2 + 5) = (4 - 8 + 5) = 1 ]

So, the limit of ( (x^2 - 4x + 5) ) as ( x ) approaches 2 is 1.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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