Home > Calculus > Determining Limits Algebraically

How do you find the limit of # (x^2 - 4x + 5) # as x approaches #2#?

Answer 1

Cameron Alexander

Substitute 2 into x: #lim(x->2) (x^2-4x+5)=(2^2-(4*2)+5)=1#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Charles Arocha

To find the limit of a function as x approaches a specific value, we can directly substitute that value into the function.

In this case, we substitute x = 2 into the function (x^2 - 4x + 5):

(2^2 - 4(2) + 5) = 4 - 8 + 5 = 1

Therefore, the limit of (x^2 - 4x + 5) as x approaches 2 is 1.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 3

Elijah Abram

To find the limit of ( (x^2 - 4x + 5) ) as ( x ) approaches 2, you can directly substitute ( x = 2 ) into the expression:

[ (2^2 - 4 \cdot 2 + 5) = (4 - 8 + 5) = 1 ]

So, the limit of ( (x^2 - 4x + 5) ) as ( x ) approaches 2 is 1.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.