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How do you find the limit of #(x^2+4)^3# as #x->2#?

Answer 1

#lim_(xrarr2) (x^2+4)^3=color(green)(512)#

Since #(x^2+4)^3# is defined when #x=2# the limit as #xrarrcolor(red)(2)# is simply #(color(red)(2)^2+4)^3=(4+4)^3=8^3= 512#

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Answer 2

Adam Adkins

To find the limit of (x^2+4)^3 as x approaches 2, we can substitute the value of 2 into the expression. Thus, the limit is equal to (2^2+4)^3, which simplifies to (4+4)^3, and further simplifies to 8^3. Therefore, the limit is equal to 512.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you find the limit of #(x^2+4)^3# as #x-&gt;2#?

How do you find the limit of #(x^2+4)^3# as #x->2#?