# How do you find the limit of #(x^2+4)^3# as #x->2#?

By signing up, you agree to our Terms of Service and Privacy Policy

To find the limit of (x^2+4)^3 as x approaches 2, we can substitute the value of 2 into the expression. Thus, the limit is equal to (2^2+4)^3, which simplifies to (4+4)^3, and further simplifies to 8^3. Therefore, the limit is equal to 512.

By signing up, you agree to our Terms of Service and Privacy Policy

- How do you find the limit of #e^(x^2-x)# as x approaches 1?
- What is the continuity of #f(t) = 3 - sqrt(9-t^2)#?
- How do you find the limit of # [sqrt (h^2 + 4h + 5) - sqrt(5)] / h # as h approaches 0?
- Evaluate the limit? #lim_(x rarr 0) x^2(cos(1/x)-1) #
- How do you find the limit of #(x^3 + 1) / (x^2 - 1)# as x approaches -1?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7