# How do you find the limit of # (x^2 + 3x - 10)# as x approaches #2^+#?

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To find the limit of a function as x approaches a specific value, we can substitute that value into the function. In this case, we substitute x = 2 into the function (x^2 + 3x - 10). By doing so, we get (2^2 + 3(2) - 10), which simplifies to (4 + 6 - 10) = 0. Therefore, the limit of (x^2 + 3x - 10) as x approaches 2^+ is 0.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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