# How do you find the limit of #((t^2)+(5t)) / (cosh(t)-1)# as t approaches 0?

so

By signing up, you agree to our Terms of Service and Privacy Policy

To find the limit of ((t^2)+(5t)) / (cosh(t)-1) as t approaches 0, we can use L'Hôpital's rule. Taking the derivative of the numerator and denominator separately, we get (2t + 5) / sinh(t). Evaluating this expression as t approaches 0, we find that the limit is 5/1, which simplifies to 5.

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- How do you prove that the function #f(x) = x^2 -3x +5# is continuous at a =2?
- How do you find the limit of #sec3xcos5x# as x approaches pi/2 from the left?
- For what values of x, if any, does #f(x) = tan((5pi)/4-x) # have vertical asymptotes?
- How do you find the limit of # x^2 sin(1/x)# as x approaches 0?
- How do I find #lim_(x->0)(2sin(x-1))#, if it exists?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7