How do you find the limit of #(sqrt(x+5)-3)/(x-4)# as #x->4#?

Answer 1

# lim_(x rarr 4) (sqrt(x+5)-3)/(x-4) = 1/6#

# lim_(x rarr 4) (sqrt(x+5)-3)/(x-4) = lim_(x rarr 4) (sqrt(x+5)-3)/(x-4) * (sqrt(x+5)+3)/(sqrt(x+5)+3)# # " " = lim_(x rarr 4) ((sqrt(x+5)-3))/((x-4)) * ((sqrt(x+5)+3))/((sqrt(x+5)+3))# # " " = lim_(x rarr 4) (sqrt(x+5)^2-3^2)/((x-4)(sqrt(x+5)+3))# # " " = lim_(x rarr 4) (x+5-9)/((x-4)(sqrt(x+5)+3))# # " " = lim_(x rarr 4) (x-4)/((x-4)(sqrt(x+5)+3))# # " " = lim_(x rarr 4) 1/(sqrt(x+5)+3)# # " " = 1/(sqrt(4+5)+3)# # " " = 1/(sqrt(9)+3)# # " " = 1/(3+3)# # " " = 1/6#
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Answer 2

To find the limit of (sqrt(x+5)-3)/(x-4) as x approaches 4, we can use algebraic manipulation and the concept of limits. First, we simplify the expression by multiplying both the numerator and denominator by the conjugate of the numerator, which is sqrt(x+5)+3. This will help us eliminate the square root in the numerator. After simplifying, we get (x-4)/(x-4)(sqrt(x+5)+3). Next, we can cancel out the common factor of (x-4) in the numerator and denominator. This leaves us with 1/(sqrt(x+5)+3). Finally, we substitute x=4 into the expression, which gives us 1/(sqrt(4+5)+3) = 1/(sqrt(9)+3) = 1/(3+3) = 1/6. Therefore, the limit of (sqrt(x+5)-3)/(x-4) as x approaches 4 is 1/6.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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