How do you find the limit of #sqrt(x+1)# as #x->3#?
Evaluate at x = 3
By signing up, you agree to our Terms of Service and Privacy Policy
To find the limit of sqrt(x+1) as x approaches 3, we can substitute the value of 3 into the expression. Thus, the limit is sqrt(3+1) = sqrt(4) = 2.
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- What is #lim_(xrarroo) (3x^3+2x+500x-1)/(x^4-8000x^3-30x) #?
- What is the limit of #((2-x)^2(3-x)^2(1-x)) / (2-x^2)^2# as x goes to infinity?
- How do you find the Limit of #(x/lnx)# as x approaches infinity?
- How do you solve for #x in RR# the equation #x! = e^x# ?
- How do you find the limit of #x^2-2x# as x approaches 2?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7