# How do you find the limit of #sinx# as #x->(5pi)/6#?

Limits of trigonometric functions may be found by substitution for values in the domain of the function.

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To find the limit of sin(x) as x approaches (5π)/6, we can directly substitute the value into the function. The sine function is continuous, so we can evaluate it at the given value.

sin((5π)/6) = -1/2

Therefore, the limit of sin(x) as x approaches (5π)/6 is -1/2.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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- How do you find the limit of #(x^3 + 1) / (x^2 - 1)# as x approaches -1?

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