# How do you find the limit of #(sin3x)/x# as #x->0#?

The limit is

By signing up, you agree to our Terms of Service and Privacy Policy

To find the limit of (sin3x)/x as x approaches 0, we can use the concept of L'Hôpital's Rule. By applying this rule, we differentiate the numerator and denominator separately with respect to x.

Differentiating sin3x with respect to x gives us 3cos3x, and differentiating x with respect to x gives us 1.

Now, we can evaluate the limit of (3cos3x)/1 as x approaches 0. Plugging in x=0 into the expression gives us 3cos(0)/1, which simplifies to 3(1)/1 = 3.

Therefore, the limit of (sin3x)/x as x approaches 0 is equal to 3.

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7