# How do you find the limit of #sin(x+4sinx)# as x approaches pi?

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To find the limit of sin(x+4sinx) as x approaches pi, we can substitute pi into the expression and evaluate it. The limit is equal to sin(pi+4sin(pi)), which simplifies to sin(pi+0) and further simplifies to sin(pi). The value of sin(pi) is 0. Therefore, the limit of sin(x+4sinx) as x approaches pi is 0.

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