# How do you find the limit of #sec((pix)/6)# as #x->7#?

Hence we can say we are finding;

Rationalising the denominator to yeild;

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To find the limit of sec((πx)/6) as x approaches 7, we can substitute the value of x into the function and evaluate it.

Substituting x = 7 into the function, we have sec((π*7)/6).

Evaluating this expression, we find that sec((π*7)/6) is equal to -1.

Therefore, the limit of sec((πx)/6) as x approaches 7 is -1.

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The limit of sec((πx)/6) as x approaches 7 does not exist.

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