# How do you find the Limit of #ln [(x^.5) + 5] /(lnx)# as x approaches infinity?

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To find the limit of ln [(x^.5) + 5] /(lnx) as x approaches infinity, we can use L'Hôpital's Rule. Taking the derivative of the numerator and denominator separately, we get (0.5/x) / (1/x). Simplifying this expression, we have 0.5 / 1, which equals 0. Therefore, the limit of ln [(x^.5) + 5] /(lnx) as x approaches infinity is 0.

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