# How do you find the Limit of #ln(x+1)/x # as x approaches infinity?

Applying L'Hospital's rule gives us

graph{ln(x+1)/(x) [-10, 10, -5, 5]}

By signing up, you agree to our Terms of Service and Privacy Policy

To find the limit of ln(x+1)/x as x approaches infinity, we can use L'Hôpital's rule. Taking the derivative of the numerator and denominator separately, we get (1/(x+1))/1. As x approaches infinity, the denominator becomes much larger than the numerator, resulting in the limit approaching 0. Therefore, the limit of ln(x+1)/x as x approaches infinity is 0.

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- For what values of x, if any, does #f(x) = 1/((2x-3)(5x-3) # have vertical asymptotes?
- How do you find the limit of #(sqrt(x+4) -2) / x# as x approaches 0?
- Calculate f prime for the following continuous function?
- How do you evaluate #sin(x-3)/(x^2+4x-21)# as x approaches 3?
- What is the limit of #f(x) = -1/(2(lnx)^2)# ?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7