# How do you find the limit of #((h-1)^2+1)/h# as h approaches 0?

By signing up, you agree to our Terms of Service and Privacy Policy

The limit is divergent.

In this case we have:

The First limit exists:

The Second limit exists

However the third limit diverges

Hence the initial limit is divergent.

By signing up, you agree to our Terms of Service and Privacy Policy

To find the limit of ((h-1)^2+1)/h as h approaches 0, we can substitute 0 for h in the expression. This gives us ((0-1)^2+1)/0, which simplifies to (1+1)/0. However, division by zero is undefined, so the limit does not exist.

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- How do you evaluate the limit #sin^2(3x)/x^2# as x approaches #0#?
- What's the difference between jump and removable discontinuity?
- How do you prove limit of #x^2-3x=-2# as #x->2# using the precise definition of a limit?
- Let #f(x)=(x^3 - 4x)/(x^3 +x^2-6x)#, how do you find all points of discontinuity of f(x)?
- How do you find the limit of # |x|/x # as x approaches #0#?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7