# How do you find the limit of #f(x)=(secx-1)/x^2# as x approaches 0?

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To find the limit of f(x)=(secx-1)/x^2 as x approaches 0, we can use L'Hôpital's Rule. Taking the derivative of the numerator and denominator separately, we get f'(x) = (secx * tanx - 0) / (2x). Evaluating the limit of f'(x) as x approaches 0, we have lim(x->0) f'(x) = (1 * 0 - 0) / (2 * 0) = 0. Therefore, the limit of f(x) as x approaches 0 is also 0.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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- How do you evaluate the limit #(x^2-25)/(x+5)# as x approaches #-5#?
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