# How do you find the limit of #(2x-1)/(abs(2x^3 - x^2))# as x is approaching 0.5 from the negative side?

Use the definition and the properties of the absolute value after factoring.

By signing up, you agree to our Terms of Service and Privacy Policy

To find the limit of (2x-1)/(abs(2x^3 - x^2)) as x approaches 0.5 from the negative side, we can evaluate the expression by substituting the value of x into the expression.

When x approaches 0.5 from the negative side, we substitute x = 0.5 into the expression:

(2(0.5)-1)/(abs(2(0.5)^3 - (0.5)^2))

Simplifying this expression gives us:

(1-1)/(abs(0.5^3 - 0.5^2))

Further simplifying:

0/(abs(0.125 - 0.25))

Since the denominator is positive, we can ignore the absolute value.

Therefore, the limit of (2x-1)/(abs(2x^3 - x^2)) as x approaches 0.5 from the negative side is 0.

By signing up, you agree to our Terms of Service and Privacy Policy

- For what values of x, if any, does #f(x) = 1/((x-3)(x^2-27)) # have vertical asymptotes?
- How do you find the limit of #x/(ln(1+2e^x))# as x approaches infinity?
- How do you prove the statement lim as x approaches 3 for #(x/5) = 3/5# using the epsilon and delta definition?
- How do you determine the limit of #[1/(x-2) + 1/(x+2)]# as x approaches 2+?
- What is the limit of #(5x-9)/(4x^3+1)# as x goes to infinity?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7