How do you find the limit of #2sin(x-1)# as x approaches 0?
I don't know if you have correctly written the excercise, because it seems really easy:
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To find the limit of 2sin(x-1) as x approaches 0, we substitute 0 into the expression:
2sin(0-1) = 2sin(-1) = 2(-0.84147) = -1.68294
Therefore, the limit of 2sin(x-1) as x approaches 0 is -1.68294.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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