# How do you find the limit of #1/t - 1/(t^2+t) # as t approaches 0?

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To find the limit of 1/t - 1/(t^2+t) as t approaches 0, we can simplify the expression first.

Combining the fractions, we get (t - 1)/(t(t+1)).

Next, we can factor the numerator as (t - 1) = -1(1 - t).

Now, we can cancel out the common factor of (t - 1) in the numerator and denominator.

This leaves us with -1/(t+1).

Finally, as t approaches 0, the denominator (t+1) approaches 1.

Therefore, the limit of 1/t - 1/(t^2+t) as t approaches 0 is -1/1, which simplifies to -1.

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