# How do you find the limit of #1+ 9/x# as x approaches #oo#?

The most important thing to recognize here is that when we have:

By signing up, you agree to our Terms of Service and Privacy Policy

To find the limit of 1 + 9/x as x approaches infinity, we can observe that as x becomes larger and larger, the value of 9/x approaches 0. Therefore, the limit of 1 + 9/x as x approaches infinity is 1.

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- For what values of x, if any, does #f(x) = 1/((5x+8)(x+4) # have vertical asymptotes?
- How do you evaluate the limit #sinx/tanx# as x approaches #0#?
- How do you find the limit #(x^3-6x-2)/(x^3-4)# as #x->2#?
- How do you find the Limit of #x^2+1# as #x->1# and then use the epsilon delta definition to prove that the limit is L?
- How do you find the removable discontinuity(hole) for the graph of #y=(x^2 - 9x -10)/ (2x^2 - 2)#?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7