How do you find the limit of # [-1/5(1-(1/x)^(4/5)]# as x approaches infinity?
Remember that
By signing up, you agree to our Terms of Service and Privacy Policy
To find the limit of the given expression as x approaches infinity, we can simplify it by applying the properties of limits.
First, let's simplify the expression inside the parentheses: (1 - (1/x))^(4/5).
As x approaches infinity, 1/x approaches 0. Therefore, we can rewrite the expression as (1 - 0)^(4/5), which simplifies to 1^(4/5) = 1.
Next, we multiply the simplified expression by -1/5: -1/5 * 1 = -1/5.
Therefore, the limit of the given expression as x approaches infinity is -1/5.
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- What is the limit of #(x^2 + 2) / (x^3 + x^2 -1)# as x approaches negative infinity?
- How do you find the limit of #[1/e^(x +1)]^sqrtx # as x approaches 0?
- How do you evaluate the limit #tan(4x)/x# as x approaches #0#?
- How do you find the limit of #sqrt(x+1)# as #x->3#?
- How do you find the limit of #(4x^2 -3x+2)/(7x^2 +2x-1)# as x approaches infinity?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7