# How do you find the limit #lim (2x^2-3x+2)/(x^3+5x^2-1)# as #x->oo#?

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To find the limit as x approaches infinity, we can analyze the highest power terms in the numerator and denominator. In this case, the highest power term in the numerator is 2x^2, and the highest power term in the denominator is x^3.

Since the power of x in the denominator is greater than the power of x in the numerator, as x approaches infinity, the denominator will dominate the fraction.

Therefore, the limit as x approaches infinity of (2x^2-3x+2)/(x^3+5x^2-1) is 0.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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