How do you find the Least common multiple of #30ab^3, 20ab^3#?

Answer 1

The LCM is #60ab^3#

#ab^3# is in both of them so we only need to look at the numbers to determine LCM.
#color(blue)("Condition 1")# The last digit in both 30 and 20 is 0. So the multiple must also end in 0.
#color(blue)("Condition 2")# The first digits are 3 and 2. The 2 means that they both have to be factors of an even number. The closest even number they both divide exactly into is 6.
#color(blue)("Combining condition 1 and 2")# 6 put with 0 gives 60
Thus the LCM is #60ab^3#
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Answer 2

The LCM is #60ab^3#.

The product of the largest amounts of each (prime) factor that appears in either number is the least common multiple (LCM) of two numbers; in other words, it is the smallest value that we can be certain will have both numbers as factors.

First, factor the two numbers.

#30ab^3# has the factors #[(2,3,5,a,b^3)]#. #20ab^3# has the factors #[(2^2, , 5, a, b^3)]#.

Step 2: Circle the larger factor after comparing the powers of each element that appears in the two numbers.

The factor #2# appears once in #30ab^3#, and it appears twice in #20ab^3#. Circle the #2^2#.
#[(2,3,5,a,b^3),( (2^2), , 5, a, b^3)]#
The factor #3# appears once in #30ab^3#, and not at all in #20ab^3#. Circle the #3#.
#[(2,(3),5,a,b^3),( (2^2), , 5, a, b^3)]#
The remaining three factors #(5, a, b^3)# appear the same number of times in both numbers. Circle either appearance of these factors.
#[(2,(3),5,a,b^3),( (2^2), , (5), (a), (b^3))]#

Step 3: Add up all of the values that are circled.

The circled values are #(2^2)(3)(5)(a)(b^3)#. The product of these values is
#60ab^3#

Our least common multiple is this one.

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Answer 3

To find the least common multiple (LCM) of 30ab^3 and 20ab^3, you need to identify the highest powers of each prime factor that appear in either expression and multiply them together.

The prime factorization of 30ab^3 is (2 \times 3 \times 5 \times a \times b^3).

The prime factorization of 20ab^3 is (2^2 \times 5 \times a \times b^3).

To find the LCM, take the highest power of each prime factor that appears in either expression:

  • For 2: The highest power is (2^2).
  • For 3: It only appears in 30ab^3, so it's (3^1).
  • For 5: The highest power is (5^1).
  • For a: It appears in both, so it's (a^1).
  • For (b^3): The highest power is (b^3).

Now, multiply these highest powers together:

(2^2 \times 3^1 \times 5^1 \times a^1 \times b^3 = 4 \times 3 \times 5 \times a \times b^3 = 60ab^3).

Therefore, the least common multiple of 30ab^3 and 20ab^3 is 60ab^3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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